I₂ (g) + Br₂ (g) ↔ 2IBr (g)
Given is Kc = 280 at 150 degree C.
Kc = [IBr]² / [I₂][Br₂]
Initially [IBr] = 0.45 / 2 = 0.225 M
The actual reaction is:
2IBr ↔ I₂ + Br₂, Kc = 1/280 = 0.00357142
In equilibrium,
[IBr] = 0.225 - 2x
[I₂] = x
[Br₂] = x
By substituting the values we get,
K = [I₂] [Br₂] / [IBr]²
0.00357142 = x×x / (0.225 - 2x)²
√(0.00357142) = x / (0.225 - 2x)
0.0597613 (0.225 - 2x) = x
0.01344 - 2 × 0.0597613x = x
(1 + 2 × 0.0597613)x = 0.01344
x = 0.01344 / (1+2 × 0.0597613)
x = 0.01344 / 1.1195226
x = 0.012005
Substituting the values we get,
IBr = 0.225 - 2 × 0.012005 = 0.17698 M
I₂ = x = 0.012005 M
Br₂ = 0.012005 M
Answer:
1. 16 protons, 18 electrons, 16 neutrons
2. Ba (2+) + 2 NO3 (-) + 2 Na (+) + SO4 (-) = 2 Na (+) + 2 NO3 (-) + BASO4
Explanation:
1. By looking at the number in the top left corner, we know the mass is 32. And by looking at the number in the bottom left, we know that we have 16 protons. Now the way to find neutrons is to subtract the number of protons from the mass (32-16) which will give us 16 neutrons. Now the electrons are a bit tricky. Usually, atoms have the same number of protons and electrons, hence why atoms don't usually have a charge. However, in this case we have a charge of 2- (as seen in the top right corner) so we need to add two to the number of protons to find our number of electrons (electrons are negatively charged, so if there are more of them the atom will have an overall negative charge) and when we do that we get 18. So the final answer is 16 protons, 18 electrons, and 16 neutrons.
2. This one I'm not 100% sure on since the pictures are kinda wonky but essentially the way net ionic equations are written is that whatever is aqueous/soluble (aq) will be written separate from whatever it was bonded to with the charge shown, but solids (s), liquids (l), and gases (g) are written still bonded without the charge being shown. So in this case, everything in the reaction is aqueous except for the BaSO4 product. The parentheses are used to show charges, but won't be written in an actual equation, and the equal sign is the same as the arrow. So you're equation is written as Ba (+) + 2 NO3 (-) + 2 Na (+) + So4 (2-) = 2 Na (+) + NO3 (-) + BaSO4.
Hope this helps! :)
The balanced net equation for
BaCl2 (aq) + H2SO4(aq) → BaSO4(s) + HCl (aq) is
Ba^2+(aq) +SO4^2- → BaSO4 (s)
<u><em>Explanation</em></u>
Ionic equation is a chemical equation in which electrolytes in aqueous solution are written as dissociated ions.
<u>ionic equation is written using the below steps</u>
Step 1: <em>write a balanced molecular equation</em>
BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s) +2HCl (aq)
Step 2: <em>Break all soluble electrolytes in to ions</em>
= Ba^2+ (aq) + 2Cl^-(aq) + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s) + 2H^+(aq) +2Cl^- (aq)
step 3: <em>cancel the spectator ions in both side of equation ( ions which do not take place in the reaction)</em>
<em> </em><em> =</em> 2Cl^- and 2H^+ ions
Step 4: <em>write the final net equation</em>
<em> Ba^2+(aq) + SO4^2-(aq)→ BaSO4(s</em><em>)</em>
