Answer:
The answer is C.
Step-by-step explanation:
Add 3 to both sides and you will get x/2=10. Multiply by the reciprocal on both sides making x=20.
Answer:
1. 38, 80, 89 and 4. 14, 15, 29
I don't know if there is supposed to be only one, but both of those do not form right triangles.
Step-by-step explanation:
Evaluate all of them and see if they meet the requirements of the Pythagorean Theorem, a² + b² = c².
1. 38, 80, 89
a² + b² = c²
38² + 80² = 89²
1444 + 6400 = 7921
7844 ≠ 7921.
This is an answer because it doesn't satisfy the Pythagorean Theorem.
2. 16, 63, 65
a² + b² = c²
16² + 63² = 65²
256 + 3969 = 4225
4225 = 4225
This isn't the answer because it satisfies the Pythagorean Theorem.
3. 36, 77, 85
a² + b² = c²
36² + 77² = 85²
1296 + 5929 = 7225
7225 = 7225
This isn't the answer because it satisfies the Pythagorean Theorem.
4. 14, 15, 29
a² + b² = c²
14² + 15² = 29²
196 + 225 = 841
421 ≠ 841
This is an answer because it does not satisfy the Pythagorean Theorem.
Answer:
b.
a.
Step-by-step explanation:
b.
a.
The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.
I am joyous to assist you anytime.
9/10 is the shorter distance
q(x)= x 2 −6x+9 x 2 −8x+15 q, left parenthesis, x, right parenthesis, equals, start fraction, x, squared, minus, 8, x, plus, 1
AURORKA [14]
According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.
<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>
Herein we know that the <em>rational</em> function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are <em>vertical</em> asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see <em>evitable</em> and <em>non-evitable</em> discontinuities:
q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)
q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]
q(x) = (x - 3) / (x - 5)
There are one <em>evitable</em> discontinuity and one <em>non-evitable</em> discontinuity. According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.
To learn more on rational functions: brainly.com/question/27914791
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