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3 years ago

Is anyone good at geometry if so can you help me please ?

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

3 0

The arcs FA, AB, and BF make up the entire circle, so their measures sum to 360°:

arcFA + arcAB + arcBF = 360° → arcBF = 360° - 160° - 140° = 60°

By the inscribed angle theorem, angle BAF has measure equal to half of that of arc BF, so

angleBAF = 30°

By the secant-tangent theorem (not sure if there's an official name for it), the measure of angle ACF is equal to half the difference of the arcs it intercepts, namely BF and FA, so that

angleACF = 1/2 (arcFA - arcBF) = 1/2 (160° - 60°) = 50°

Now use the law of sines for solve for FA:

sin(angleACF) / FA = sin(angleBAF) / FC

sin(50°) / FA = sin(30°) / 10

FA = 10 sin(50°) / sin(30°) ≈ 15.3

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2

fredd [130]

Answer:

Both get the same results that is,

$\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

Step-by-step explanation:

Given :

$\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

and initial population,

$\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]$

a) - After two times, we will find in each position.

$P_2=[P].[M]^2=[P].[M].[M]$

$M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

$=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

b) - With in migration process, 500 people are numbered. There will be after a long time,

$After\;inifinite\;period=[M]^n.[P]$

$Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

4 0

3 years ago

Find the value of A in the equation 5/a+3=3/A-2

amid [387]

5+3a = 3-2a
So
5a = -2
a=-2/5=-0.4

4 0

3 years ago

Read 2 more answers

25 POINTS!! (EASY)MORE POINTS!!!!!!! BRAINLIEST PLSSSSSSSSSSSSSSSSSSSHELP. For Brainliest Please help)

Lostsunrise [7]

Answer:

A) 50

B) 20

C) 20

Step-by-step explanation:

To solve the first question, we can multiply both sides by 10.

Thus, we get:

6x = 300.

Then, divide by 6, to get x:

x = 50.

You can do the same thing to all of these questions.

I've already checked the answers, but if you don't trust them, just pluck the values in.

For example, let's check the answer for question A.

0.6*50 is supposed to equal 30.

Does it equal? Yes, so we know that the answer is correct.

3 0

3 years ago

Which point is closest to the x axis. (4, 8) (2, 11) (8, 7) (3, 13)

ohaa [14]

Answer: 8,7
Step by step:
Because the numbers on the left sides are numbers that represent the y-axis which is how far up or down the point will be.
7 is the smallest number making it the closest to the x- axis.
Hope this helped you:)

5 0

3 years ago

What is the distance between M(9, −5) and N(−11, 10)?

lesya692 [45]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}$