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allochka39001 [22]
3 years ago
15

Can anybody do these for me hurry ?

Mathematics
2 answers:
Damm [24]3 years ago
8 0

Answer:

- Mode-The most repetitive number.

- Median:The number in the MIDDLE when they are IN ORDER.

- Mean- The AVERAGE OF ALL NUMBERS: You add up all the numbers then you divide it by the TOTAL NUMBER of NUMBERS.

- Range - THE BIGGEST minus the Smallest.

Step-by-step explanation:

;)

exis [7]3 years ago
7 0

Answer:

mean: average of all the numbers, so add all numbers, divide by the amount of numbers you added

median: sort all the numbers from least to greatest, then the middle is the answer, if there are 2 in the middle, both are the answer

mode: the number that appeared most

range: the largest number minus the smallest number

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Mixed numbers between 5 and 7 with an interval of 1/3
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5 1/3 , 5 2/3 , 5 3/3 , 6 1/3 , 6 2/3 ,
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Change the fraction 7/12 to a decimal. Round your answer to the nearest thousandth. A. 1.714 B. 1.700 C. .600 D. .583
mrs_skeptik [129]
Divide

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Write 3% two different ways. Explain how you know this.
Marysya12 [62]

Answer:

0.03

3/100

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3 0
2 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
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