Answer:
<h2>D= 3.9 miles</h2>
Step-by-step explanation:
Given data
speed v= 13 miles per hour
time taken t= 20min to hour 0.3 hours
the distance D
We know that the relationship between speed, time, and distance
speed=distance/time
13=D/0.3
(the expression above describes the relationship between distance, speed, and time)
making D subject of formula we have
D= 0.3*13
D= 3.9 miles
hence the distance is 3.9miles
Answer: Red copper = $0.12 per meter
Yellow copper = $0.22 per meter
Step-by-step explanation:
Since Red copper costs $0.90 for 7.6m, the cost of 1m of red copper will be:
= $0.90/7.6
= $0.12
Since yellow copper costs $1.12 5.2m, the cost of 1m of yellow copper will be:
= $1.12 / 5.2
= $0.22 per meter
common difference = 2nd term - 1st term
= 13 - 4
= 9
Answer:
-2 and 24
Step-by-step explanation:
the trend line is linear,
let the unknowns be A and B
hence the equation becomes
K = AJ + B
from the graph we can see the following:
when J = 0, K = 24 (substitute this into the equation)
K = AJ + B
24 = A(0) + B
24 = B (Answer)
Also notice that when K = 0, J = 12
together with our previous finding that B = 24, the equation becomes:
K = AJ + B
0 = A(12) + 24
12A = -24
A = -24 / 12
A = -2 (answer)
Answer:
See explanation
Step-by-step explanation:
Solution:-
- The effect of an outlier on the mean, median and range is to be investigated.
- Mean: It is the average of all the values. If the outlier "22" is lies on the upper spectrum of the center value. If the outlier is removed the value of center or mean will decrease.
- Median: The median value is mostly defined as the value around which their is a cluster of data. The value of the outlier "22" if close to that cluster of data points is omitted there will be small deviation in the value of median. If the value of the outlier "22" if far away to that cluster of data points is omitted there will be significant deviation in the value of median.
- Range: Is defined by the uppermost and lowermost value from a set of data points that is considered. The value of outlier will equally effect either of these limits depending where the outlier lies close to upper limit or lower limit of the range.
