If triangle KMN is congruent with triangle LMN, then:
1) KM must be congruent with LM→KM=LM→
x+2y=3x-y→x+2y-x-2y=3x-y-x-2y→0=2x-3y→2x-3y=0 (1)
2) KN must be congruent with LN→KN=LN→
5x+3y=8x-7→5x+3y-5x-3y+7=8x-7-5x-3y+7→7=3x-3y→3x-3y=7 (1)
We have a system of two equations and two unkowns:
(1) 2x-3y=0
(2) 3x-3y=7
Subtracting equation (1) from equation (2)
(3x-3y)-(2x-3y)=7-0
3x-3y-2x+3y=7
x=7
Replacing x=7 in equation (1)
(1) 2x-3y=0→2(7)-3y=0→14-3y=0→
14-3y+3y=0+3y→14=3y→14/3=3y/3→14/3=y→y=14/3
The length of the hypotenuse is:
KN=5x+3y=5(7)+3(14/3)=35+14→KN=49
or
LN=8x-7=8(7)-7=56-7→LN=49
Answer: Option C. 49
Answer: (y ÷ 4) - 3
Quotient ⇒ division
Answer:
x=4
Step-by-step explanation:
1. 2x+4=12
2. 2x+4-4=12-4
3. 2x=8
4. 2x/2=8/2
5. x=4
<u>Let's take this problem step-by-step</u>:
<u>Let's first set up some variables</u>:
- c: # of children
- a: # of adults
<u>Let's examine the information given:</u>
- Elevator can hold a maximum of 1500 pounds
⇒ average child is 75 pounds
⇒ average adult is 150 pounds
⇒<em> therefore</em>:
- Elevator can fit no more than 14 people
⇒ <em>therefore</em>:
<u>Let's graph the equations</u>:
⇒ look at the image attached
<u>The point at which the two graphs intersect:</u>
⇒ <em>is the solution that represents the amount of children and adults and </em>
<em> their combine weight</em>
<em />
<u><em>With the horizontal axis being the # of children and vertical axis being the # of adults</em></u><em>:</em>
<em> ⇒ the </em><em>solution is 8 children and 6 adults</em>
<em></em>
<u>Answer: 8 children and 6 adults</u>
<u></u>
Hope that helped!
<em />
Answer:
medio pastel cada uno
Step-by-step explanation:
Hay 3 hermanos, si decimos que un pastel entero tiene 6 pedazos entonces su fraccion seria 6/6. Si dividimos este pastel entre los tres hermanos cada uno tendria...
=
Medio pastel seria la mitad de 6/6 que seria 3/6. Si dividimos esto entre los 3 hermanos cada uno tendria...
Ahora que dividimos los 2 pasteles tenemos que unir las fracciones para saber cuanto pastel le toco a cada hermano...
o medio pastel cada uno