Given:
Atul has
lb of candy.
Jose has
lb of candy.
Maria has
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has
lb less than Jose, therefore
Maria has =
lb
Maria has =
lb
Maria has =
lb
Difference between the candies Atul and Maria have.
Difference =
lb
Difference =
lb
Difference =
lb
Therefore, Atul have
lb of candy more than Maria.
Answer:
8
Step-by-step explanation:
2*1*4=8
Answer:
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Step-by-step explanation:
Given


Required
Determine the %decrease
First, we need to determine the amount paid



The percentage decrease is the calculated as follows:

In this case;


So; we have:





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<em> (Approximated)</em>
Answer:
8xy-3y + 2(9x-5y+4) = 18
Step-by-step explanation:
We need to find the value of the given expression:
8xy-3y + 2(9x-5y+4) ....(1)
when x = 3 and y = -4
Put the values of a and y in equation (1)
8×3×(-4)-3(-4)+ 2(9×3-5(-4)+4)
= -96 +12 + 2(27 + 20 +4)
= -84 + 2(51)
= -84 + 102
= 18
Hence, the value of the given expression is 18.