First, substitute -2 into each equation where there is an <span>x:
</span>(-2)2 -8<span>
</span>(-2) +6
Then multiply the -2 and the 2 in the first equation and add -2 and 6 in the second:
-4 -8
4
Lastly, subtract -4 and 8:
-12
4
Now you have you answers -12 and 4!
The answer is(99+15)11
i hope this help
Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
Remember the properties of logarithms. If you have ln81, you can pull out the power of two (9^2) and have 2ln9. Also, you could do ln9 + ln9 because 9*9=81 and ln9*9 = ln9 + ln9
With these properties, you can get 3lnx+2lny, which is 3u+2v according to the answer.
Hope I helped!
Answer: 
You can write this as (-infinity, 7) if you aren't able to use the infinity symbol.
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Explanation:
Think of x < 7 as writing 
So x is between negative infinity and 7, excluding both endpoints.
To write in interval notation, we write
The curved parenthesis tell us to exclude the endpoint.
