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miss Akunina [59]
3 years ago
13

Please someone what is the total surface area of this pryamid ​

Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

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<span> Nina + her 5 friends = 6 people
Then she has 9 apple to share with her and her friends.
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6x - 2y > 8

<u><em>First, solve the inequality (Isolate the y-variable & put it in function format):</em></u>

<u><em /></u>6x - 2y > 8\\-2y > 8 - 6x\\(-1)(-2y) > (-1)(8-6x)\\2y < 6x-8\\y < \frac{6x-8}{2} \\y < 3x - 4

<u><em>Second, graph the function y = 3x - 4 on the graph.</em></u>

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