Subtract:<br> (6m + 12) - (2m

Plz Help me with this math problem

WITCHER [35]

Because he added them up , instead of trying to find the mean ( average ) of his city's high temperatures.

3 0

3 years ago

Complete the table of values below so that it represents a line with a constant rate of change of `-\frac{3}{4}.`

Nady [450]

To find values of the table, plug in the given corresponding values of x or y, and constant rate of change (m) = -3/4 into y = mx.

<h3>What is the Constant Rate of Change?</h3>

Constant rate of change of any table or function is a comparison of how two variables are changing, which can be determined using the formula, m = change in y/change in x = $\frac{y_2 - y_1}{x_2 - x_1}$ .

Where x and y are the coordinates of a table or functions, and m is the constant rate of change, the equation that models the relationship would be, y = mx.

The image of the table is missing, however, to complete the given table, plug in any of the given values of x or y, and constant rate of change (m) = -3/4 into y = mx.

Learn more about constant rate of change on:

brainly.com/question/10866779

6 0

3 years ago

First derivative of <br>√{cosec2x).show with full step.

Mice21 [21]

Answer:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

Step-by-step explanation:

we are given a derivative

$\displaystyle \: \frac{d}{dx} ( \sqrt{ \csc(2x) } )$

and said to figure out the first derivative

to do so

recall chain rule:

$\sf\displaystyle \: \frac{d}{dx} (f(g(x)) = \frac{d}{dg} (f(g(x)) \times \frac{d}{dx} (g)$

so we get

$\displaystyle \: g(x) = \csc(2x)$

rewrite the derivative using the chain rule:

$\displaystyle \: \frac{d}{dg} ( \sqrt{ g } ) \times \frac{d}{dx} ( \csc(2x) )$

use square root derivative rule to simplify:

$\displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dx} ( \csc(2x) )$

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dn}( \csc(n) ) \times \frac{d}{dx} (2x)$

use derivative formula to simplify derivatives:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - \cot(n) \csc(n) \times 2$

substitute the value of n:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - 2\cot(2x) \csc(2x)$

substitute the value of g:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2\cot(2x) \csc(2x)$

now we need our trigonometric skills to simplify

rewrite cot and csc:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2 \dfrac{ \cos(2x) }{ \sin(2x) } \dfrac{1}{ \sin(2x) }$

simplify multiplication:

$\sf \displaystyle \: \frac{1}{ \cancel{ \: 2}\sqrt{ \csc(2x) } } \times \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }$

simplify multiplication:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

4 0

3 years ago

Read 2 more answers

Solve the system of linear equations by multiplying. Check the answer by graphing the system of equations. –2x + 2y = 10 -4x + 5

kari74 [83]

Answer:

x=2, y=7 (2,7)

Explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

8 0

3 years ago

Find the y-intercept and the x-intercept of the line 2x-4y=10

kompoz [17]

Finding y intercept and x intercept is easy:

X intercept will be of the form (x,0) and y intercept will be of the form (0,y)

● If you put x=0 in the equation, you will get y-intercept.

● If you put y=0 in the equation, you will get x-intercept.
______________________________

Given equation: 2x - 4y = 10

◆ Put x = 0
2×0 - 4y = 10
=> -4y = 10
=> y = 10/(-4)
=> y = -5/2

Thus y intercept is (0, -5/2)

◆Put y = 0
2x - 4×0 = 10
=> 2x = 10
=> x = 10/2
=> x = 5

Thus the x intercept is (5,0)

4 0

3 years ago

Subtract: (6m + 12) - (2m – 8)