Answer:the z score is - 1
Step-by-step explanation:
Assuming a normal distribution for the delivery time of sandwiches by Sammy's Sandwich Shop. We would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = delivery times
u = mean delivery time
s = standard deviation
From the information given,
u = 25 minutes
s = 2 minutes
We want to determine the z-score for the number of sandwiches delivered in less than 23 minutes. It becomes
z = (23 - 25)/2 = - 1
Answer:
5L/2 < 100
Step-by-step explanation:
Let's get started!
Let :
⇒ Length = L
⇒ Width = L/4
It mentions the perimeter must be less than 100 inches.
Perimeter Formula :
<u><em>Perimeter (Rectangle) = 2(Length + Width)</em></u>
Then, the inequality formed will be :
⇒ 2 (L + L/4) < 100
⇒ 2 (5L/4) < 100
⇒ 10L/4 < 100
⇒ 5L/2 < 100
It would be d because youing the point slope equation which is (y - y1) = m (x- x1) when distributing the point and the slope into the equation asl well as sinplifying youll get D. Y1 is the value of the y in the ordered pair and x1 is the x value of the ordered pair.
First, move like terms on one side. Next, add them and divide. See the attachment for solution.
Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that
you can clear the intersection from the formula
and apply it for the given events:
![P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07](https://tex.z-dn.net/?f=P%28A_1nB%29%3D%20P%28B%2FA_1%29%20%2A%20P%28A_1%29%3D%200.20%2A0.35%3D%200.07)
![P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025](https://tex.z-dn.net/?f=P%28A_2nB%29%3D%20P%28B%2FA_2%29%2AP%28A_2%29%3D%200.05%2A0.50%3D%200.025)
c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:
![P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}](https://tex.z-dn.net/?f=P%28Ai%2FB%29%3D%20%5Cfrac%7BP%28B%2FAi%29%2AP%28A%29%7D%7BP%28B%29%7D)
Then:
![P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74](https://tex.z-dn.net/?f=P%28A_1%2FB%29%3D%20%5Cfrac%7BP%28B%2FA_1%29%2AP%28A_1%29%7D%7BP%28B%29%7D%3D%20%5Cfrac%7B0.20%2A0.35%7D%7B0.095%7D%3D%200.737%20%3D%200.74)
![P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26](https://tex.z-dn.net/?f=P%28A_2%2FB%29%3D%20%5Cfrac%7BP%28B%2FA_2%29%2AP%28A_2%29%7D%7BP%28B%29%7D%20%3D%20%5Cfrac%7B0.05%2A0.50%7D%7B0.095%7D%20%3D%200.26)
I hope it helps!