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aleksklad [387]
3 years ago
11

Q3) f(x) 2x^2 - 5x, g(x) = 3x^3 find g(4x)

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

g(4x) = 192x^3

Step-by-step explanation:

For this problem, f(x) is irrelevant since we are simply are dealing with g(x).  We will simply replace the value of x in g(x) with 4x.  So let's do that.

g(x) = 3x^3

g(4x) = 3(4x)^3

g(4x) = 3(4^3)(x^3)

g(4x) = 3(64)(x^3)

g(4x) = 192x^3

Hence, g(4x) is 192x^3.

Cheers.

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The hypotenuse of a right triangle is 15cm, and the shorter leg is 9cm. Find the length of the other leg
pishuonlain [190]

Hello!

If you add up the squares of the two legs, it will equal the square of the hypotenuse. As we already have the hypotenuse, we will subtract.

225-81=144

Now we find the square root.

√144=12

Therefore, the other leg is 12 cm long.

I hope this helps!

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The formula for the perimeter of a rectangle is P = 2L + 2W. The length of a rectangle is 3 times its width. Which expression re
omeli [17]

The perimeter of a rectangle is given by the following formula:     P = 2W + 2L

To solve this formula for W, the goal is to isolate this variable to one side of the equation such that the width of the rectangle (W) can be solved when given its perimeter (P) and length (L).

     P = 2W + 2L

          subtract 2L from both sides of the equation

     P - 2L = 2W + 2L - 2L

     P - 2L = 2W

           divide both sides of the equation by 2

     (P - 2L)/2 = (2W)/2

     (P - 2L)/2 = (2/2)W

     (P - 2L)/2 = (1)W

     (P - 2L)/2 = W

Thus, given that the perimeter (P) of a rectangle is defined by    P = 2W + 2L ,

   then its width (W) is given by    <span>W = (P - 2L)/2</span>

3 0
3 years ago
Suppose you write a system of equations to find out which of two video stores is cheaper to join, depending on the number of vid
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The right answer is c
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Step-by-step explanation:

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The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School
storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

x =  \frac{206}{3}  -  \frac{7y}{6} .............3

subs 3 into 2

6( \frac{206}{3}  -  \frac{7y}{6} ) + 9y = 504

412 - 7y + 9y = 504

- 7y + 9y = 504 - 412

2y = 92

y = 46...................4

subs 4 into 1

6x + 7(46) = 412

6x + 322 = 412

6x = 412 - 322

6x = 90

x = 15

Therefore there are 15 students in each van and 46 students in each bus.

3 0
3 years ago
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