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levacccp [35]
3 years ago
6

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics
2 answers:
yuradex [85]3 years ago
7 0
Point Form:
(2,5)

x=2, y=5
Schach [20]3 years ago
5 0

Answer:

(1.3)(2.5)(3.7)(4.9)(5.11)

(1.1)(2.5)(3.9)(4.13)(5.17)

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Consider the vector x: x <- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Opti
Nookie1986 [14]

<u>Completed Question</u>

Outputs to be matched to the functions are:

  • 1,2,3,4,5
  • 1,5,3,2,4
  • 1, 4, 3, 5, 2
  • 2, 18, 27, 43, 96

Answer:

  • sort(x): 2, 18, 27, 43, 96
  • order(x): 1, 5, 3, 2, 4
  • rank(x) : 1, 4, 3, 5, 2
  • none of these :  1, 2, 3, 4, 5

Step-by-step explanation:

Given the vector x: x <- c(2, 43, 27, 96, 18)

<u>Sort</u>

In R, the sort(x)  function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.

Therefore, the output that matches the sort function is:

sort(x): 2, 18, 27, 43, 96

<u>Rank</u>

The rank function returns a vector with the "rank" of each value.

x <- c(2, 43, 27, 96, 18)

  • 2 has a rank of 1
  • 43 has a rank of 4
  • 27 has a rank of 3
  • 96 has a rank of 5
  • 18 has a rank of 2

Therefore, the output of rank(x)  is: 1, 4, 3, 5, 2

<u>Order</u>

When the function is sorted, the order function gives the previous location of each of the element of the vector.

Using the sort(x) function, we obtain: 2, 18, 27, 43, 96

In the vector: x <- c(2, 43, 27, 96, 18)

  • 2 was in the 1st position
  • 18 was in the 5th position
  • 27 was in the 3rd position
  • 43 was in the 2nd position
  • 96 was in the 4th position

Therefore, the output of order(x) is: 1, 5, 3, 2, 4

7 0
3 years ago
The storage container below is in the shape of a rectangular prism with a height of 6 feet and a length that is 2 feet more than
yaroslaw [1]

The answer is B.) V = 6w2 + 12w

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=
KiRa [710]
e ^{2x} = ln5

Solve for the real domain

e ^{2x} = ln(5)

if f(x) =g(x), then ln(f(x))= ln(g(x))

ln(e ^{2x} ) = ln(ln(5))

Solve : <span>ln(e ^{2x} ) = ln(ln(5))
</span>
use the logarithmic definition :

ln(e^{f(x)} ) = f(x)

ln(e^{2x} ) = 2x

2x=ln(ln(5))

Divide both sides by 2 :

\frac{2x}{2} = \frac{ln(ln(5))}{2}

x= \frac{ln(ln(5))}{2}

hope this helps!

8 0
3 years ago
Can someone please help me answer these 6 questions?
Mamont248 [21]
1) 19.25

2) 12.92

3) 25.20

4) 19.68

5) 77.05

6)81.67
8 0
3 years ago
Pls help!! I promise ill mark brainlest
babunello [35]

Answer:

A

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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