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vova2212 [387]
3 years ago
6

Help on precal, what are the answers?

Mathematics
1 answer:
Sloan [31]3 years ago
5 0
1) cscΘ = - 2

=>

        1
      ------ = - 2
      sinΘ

=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant

=> Θ = 180° + 30° = 210°

and Θ = 360° + 30° = 330°

2) tan Θ = √3

=> Θ = 60° and Θ = 180° + 60° = 240°
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Solve the inequality for n 14
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14n

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Subtract 1 + ( - 1 ) - ( - 3 ). Hint: Add the first two numbers, then subtract the -3 from the result of that addition
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A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra
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The Quadrilateral is JKLM, 

let M_{JK}, M_{KL}, M_{LM}, M_{JM}, be the midpoints of JK, KL, LM and JM respectively.

---------------------------------------------------------------------------------------------------------

Given any 2 point P(m,n) and Q(k,l),<span>

the coordinates of the midpoint of the line segment PQ are given by the formula:

M_{PQ}=( \frac{m+k}{2} ,&#10;\frac{n+l}{2}), </span>

-------------------------------------------------------------------------------------------------

thus the coordinates of points M_{JK}, M_{KL}, M_{LM}, M_{JM},

are as follows:

M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)


------------------------------------------------------------------------------------------------

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

 |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}&#10;}</span>

------------------------------------------------------------------------------------------------

thus the distances connecting the opposite entrances can be calculated as follows:


|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5

|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39


Thus the total distance of the paths joining the opposite entrances is 

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)


Answer: 104 m



8 0
2 years ago
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Answer:

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