Answer:
f(x)= 1.8x + 1
Step-by-step explanation:
Just got it right on edge :)
Answer:x
=
5
toppings
Step-by-step explanation:Total cost of cheese pizza:
$
10.75
Any additional topping adds:
+
$
1.25
So a cheese pizza with
1
additional topping is:
$
10.75
+
$
1.25
=
$
12.00
A cheese pizza with
2
additional toppings is:
$
10.75
+
$
1.25
+
$
1.25
=
$
10.75
+
2
×
$
1.25
=
$
13.25
A cheese pizza with
3
additional toppings is:
$
10.75
+
$
1.25
+
$
1.25
+
$
1.25
$
10.75
+
3
×
$
1.25
=
$
14.50
If you pay attention to the pattern you can see that, for any number of toppings, say
x
toppings, the price is going to be:
$
10.25
+
x
×
$
1.25
We are told the final cost is
$
17.00
. That is
$
10.25
+
x
×
$
1.25
=
$
17.00
Subtract
$
10.25
from both sides
$
10.25
−
$
10.25
+
x
×
$
1.25
=
$
17.00
−
$
10.25
x
×
$
1.25
=
$
6.25
Divide both sides by
$
1.25
x
×
$
1.25
$
1.25
=
$
6.25
$
1.25
x
=
5
Answer:
x=75
Step-by-step explanation:
Answer:
Step-by-step explanation:
given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
Clerk I II III total
Pack 0.33 0.23 0.44 1
Defective 0.02 0.025 0.015
Pack&def 0.0066 0.00575 0.0066 0.01895
a) probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate
= P(II clerk) -P(II clerk and defective) = 
b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)
=0.01895
c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3
=P(clerk 3 and def)/P(defective)
=