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Vanyuwa [196]
3 years ago
9

Anybody wana play 2k21

Computers and Technology
2 answers:
Vaselesa [24]3 years ago
4 0

Answer:

no

Explanation:

no

Pavlova-9 [17]3 years ago
3 0

Answer:I’ll play

Explanation:

You might be interested in
Write c++ program to find maximum number for three variables using statement ?​
pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

<em>if(n1>=n2 && n1>=n3){</em>

<em>cout<<n1<<" is the maximum";}</em>

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

<em>else if(n2>=n1 && n2>=n3){</em>

<em>cout<<n2<<" is the maximum";}</em>

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

<em>else{</em>

<em>cout<<n3<<" is the maximum";}</em>

return 0;

3 0
3 years ago
____ is suitable for what are called "high-volume service control applications" such as dial-in access to a corporate network.
Levart [38]

Answer: a. RADIUS

Explanation:

RADIUS as developed with the idea of allowing its users or clients to be able to authenticate to a dial-in access server. So basically it is a client server protocol and he client here is the firebox and the server is the RADIUS server.  

The authentication mechanism start by user who sends a message to the RADIUS server. Then the RADIUS server upon receiving the message accept or denies it. It accepts if the client is configured to the server.

A large amount of additional information can be sent by the RADIUS server in its Access-Accept messages with users so we can say that RADIUS is uitable for what are called "high-volume service control applications" such as dial-in access to a corporate network.

3 0
3 years ago
You enter information by keying it into the??​
Greeley [361]

Answer:

password and username

Explanation:

3 0
3 years ago
Read 2 more answers
From the binary search algorithm, it follows that every iteration of the while loop cuts the size of the search list by half.
Colt1911 [192]

Answer:

True: In binary search algorithm, we follow the below steps sequentially:

Input: A sorted array  B[1,2,...n] of n items and one item x to be searched.

Output: The index of x in B if exists in B, 0 otherwise.

  1. low=1
  2. high=n
  3. while( low < high )
  4.  {      mid=low + (high-low)/2
  5.         if( B[mid]==x)
  6.          {
  7.             return(mid)  //returns mid as the index of x
  8.           }
  9.          else
  10.          {
  11.              if( B[mid] < x)      //takes only right half of the array
  12.               {
  13.                 low=mid+1
  14.               }
  15.              else               // takes only the left half of the array
  16.               {
  17.                high=mid-1
  18.               }
  19.           }
  20.  }
  21. return( 0 )

Explanation:

For each iteration the line number 11 or line number 15 will be executed.

Both lines, cut the array size to half of it and takes as the input for next iteration.

6 0
4 years ago
Can someone please help me in answering this!?! <br> The language is C++
Llana [10]

Here is a somewhat cryptic solution that works:

#include <algorithm>

#include <cstdlib>

using namespace std;

void q(char c, int count)

{

for (int i = 0; i < count; i++) {

 putchar(c);

}

}

void p(int b1, int plusses)

{

q(' ', b1);

q('+', plusses);

}

int main()

{

for (int i = -3; i <= 3; i++)

{

 int pl = min(6, (3 - abs(i)) * 2 + 1);

 p(6-pl, pl);

 i == 0 ? p(0, 6) : p(6, 0);

 p(0, pl);

 putchar('\n');

}

getchar();

}


5 0
4 years ago
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