Question

F(x)=x^2-2x+3 g(x)=x^2-2x-4 Find f(g(-2)

Answer 1

Answer:

$f(g(-2))=11$

Step-by-step explanation:

We are given the two functions:

$f(x)=x^2-2x+3\text{ and } g(x)=x^2-2x-4$

And we want to find:

$f(g(-2))$

We will find g(-2) first. So:

$g(-2)=(-2)^2-2(-2)-4=4+4-4=4$

Thus:

$f(g(-2))=f(4)$

Evaluate:

$f(4)=(4)^2-2(4)+3=16-8+3=11$

Therefore:

$f(g(-2))=11$