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3 years ago

I need help ASAP please

Mathematics

1 answer:

svetoff [14.1K]3 years ago

6 0

Answer: 23

Step-by-step explanation:

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You have a 5” by 7” photo that you would like to have enlarged to fit an 8” by 10” frame. Would the two photographs be similar?

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No, 2 of the 5x7 would actually take up. 10x14

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3 years ago

The perimeter of the base of a regular quadrilateral prism is 32 cm. The height of the prism is 2 times greater than the length

horsena [70]

A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.

Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.

Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.

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3 years ago

Solve the equation in Slope-intercept form 2x-y=3

Ostrovityanka [42]

Answer:

Slope intercept form for 2x - y = 3 is y = 2x - 3

7 0

3 years ago

Read 2 more answers

3 times the sum of b and f can also be written as

Troyanec [42]

3 times the sum of b and f can also be written as $3(b+f)$

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3 years ago

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let X = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, λ = 11/ hour.

The random variable X follows a Poisson distribution with parameter λ = 11.

The probability mass function of X is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in t hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of t as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

3 years ago