1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio039 [100]
3 years ago
11

An open-top box is formed by cutting squares out of an 11 inch by 17 inch piece of

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Given:

The volume V(x) in cubic inches of this type of  open-top box is a function of the side length x in inches of the square cutouts and can be given by

V(x)=(17-2x)(11-2x)(x)

To find:

The above equation by expanding the  polynomial.

Solution:

We have,

V(x)=(17-2x)(11-2x)(x)

Using distributive property, we get

V(x)=[17(11-2x)-2x(11-2x)](x)

V(x)=[17(11)+17(-2x)-2x(11)-2x(-2x)](x)

V(x)=[187-34x-22x+4x^2](x)

Combining likes terms, we get

V(x)=[187-56x+4x^2](x)

Using distributive property, we get

V(x)=187x-56x^2+4x^3

V(x)=4x^3-56x^2+187x

Therefore, the required equation after expanding the  polynomial is V(x)=4x^3-56x^2+187x.

You might be interested in
A share of stock in the bree medical supply company is quoted at 35 1/4,suppose you hold 20 shares of that stock which you bough
kodGreya [7K]
Hi there, we know the total number of stocks bough is 20, the rate was 31 1/2=63/2, 20*63/2=10*63=630 dollars, the rate they were sold is 35 1/4=141/4 dollars, 5*141=705 dollars, the amount of profit is 20 stocks. So, 705-630=75 dollars. So, the answer is C. You made a profit of $75.00
5 0
3 years ago
Read 2 more answers
Multiply.
Evgesh-ka [11]
The answer is -2.76.

Hope I Helped                                   (=^-^=)
8 0
3 years ago
Read 2 more answers
Craig went out to a restaurant for dinner. He tipped 16% of his bill, which brought the sum of the dinner bill plus the tip to $
alexira [117]
$22.50

You can get this by dividing the new total by 116%, which is how much of the bill was paid. 
4 0
4 years ago
How do you solve: secx=-5/2, tanx&lt;0<br><br> Find all six trig functions
Brut [27]

Answer:

sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21

Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

5 0
3 years ago
Will give brainliest PLs help Here is the argument you are presenting: There is a need for students to understand and be able to
Natasha2012 [34]

1. It is easier to apply it to real-world situations once you have learned to construct geometric figures using compasses and straightedges.

2. Constructing geometric figures yourself also helps you understand the material and learn easily.

3. There is more accuracy and it is easier to prove your accuracy in your own constructions.

I hope this helps :)

4 0
3 years ago
Other questions:
  • There are seven boys and seven girls in a class. The teacher randomly selected one student to answer a question. Later, the teac
    14·2 answers
  • 784.5, 78.45, 7.845 find the next two numbers
    5·2 answers
  • Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass
    12·1 answer
  • Liam has 5 kg of plant food. If he uses 25 g of the food on each plant, how many plants can he feed?​
    10·1 answer
  • Which is a correct description of the polygon?
    7·2 answers
  • Subtracting 3xy2 from 8xy2 gives the same result as the expression
    5·1 answer
  • PLZ help pic included
    8·1 answer
  • I givee brainlilstttt
    6·2 answers
  • Hey! please help i’ll give brainliest:)
    10·2 answers
  • I need answers asap! | Some blocks are stacked as shown. The face of each block is a square and each block represents one cubic
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!