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creativ13 [48]
3 years ago
8

Here are four digits.

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

23

sorry if I'm wrong, I just guessed..

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A) Let f(x) = 4x + 2 and g(x) = 2x^2-4. Find the formula for the composition function gof
ollegr [7]

Answer:

g o f = g(f(x)) = 32x^2 + 32x + 4

Step-by-step explanation:

Given

f(x) = 4x +2

g(x) =2x^2 - 4

Required:

Find g o f

This is calculated as:

gof = g(f(x))

g(x) =2x^2 - 4

So:

g(f(x)) = 2(4x+2)^2 - 4

g(f(x)) = 2(4x+2)(4x+2) - 4

g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4

g(f(x)) = 32x^2 + 32x + 8 - 4

g(f(x)) = 32x^2 + 32x + 4

5 0
3 years ago
How do you find the slope.and y-intercept of y= 1/3-2
NikAS [45]

Answer:

The slope in that equation is 1/3 so you would go up on the coordinate plane one, and over three. The y intercept, is 2. Any linear equation in slope intercept form, y=mx+b,  will be set up that way, so hopefully this helps, it's the easiest way to find the slope and y intercept, m is always the slope, and b is always the y intercept. :)

4 0
3 years ago
Ples help meeeeeeeee
svetoff [14.1K]

Answer:

6610

Step-by-step explanation:

Move the decimal 2 spots to the right and add 2 zeros more behind the 528.8

so its becomes 8 divide what that number is

3 0
3 years ago
Read 2 more answers
Comparing Step Functions
maks197457 [2]

Hello, if you want help I can help you!

So, your answers should be A and D

If I'm wrong correct me.

5 0
3 years ago
Read 2 more answers
D.sqrt(2+x^/2)<br> Solve this question please
lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

y = \sqrt{4 + a*x^2}

y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

y' = \frac{x*y}{2 + x^2}

replacing y' and y we get:

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

Now we can try to solve this for "a".

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

If we multiply both sides by y(x), we get:

\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}

a*x = \frac{x*(4 + a*x^2)}{2 + x^2}

We can remove the x factor in both numerators if we divide both sides by x, so we get:

a = \frac{4 + a*x^2}{2 + x^2}

Now we just need to isolate "a"

a*(2 + x^2) = 4 + a*x^2

2*a + a*x^2 = 4 + a*x^2

Now we can subtract a*x^2 in both sides to get:

2*a = 4\\a = 4/2 = 2

Then the solution is:

y = \sqrt{4 + 2*x^2}

The correct option is option a.

7 0
2 years ago
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