You’re trying to find x which is the side opposite to the angle. You’re given the adjacent angle. To find the variable, you use tangent. So you plug in tan(x)= opposite/adjacent. In this case it would be tan(27)=x/15. Then you multiply both sides by 15 to be 15(tan(27))=x which is 7.6=x
11.5, when rounded to the nearest tenth the answer was 11.468 but we need to round and 6 is 5 and higher so the 4 would become a 5. The answer is 11.5
Answer:
Rectangle 1: 84 ft^2 Rectangle 2: 8 ft^2
Step-by-step explanation:
Split the figure into two rectangles
Rectangle 1:
Width of rectangle 1 can be found by subtracting 8 ft from 15 ft
15-8=7 ft (width)
length is already given as 12 ft
So,
A = L x W
A = 12ft x 7 ft
A = 84 ft^2
Length is already given of one of the rectangles
Rectangle 2:
Finding the width of Rectangle 2 can be found by subtracting 11 ft from 12 ft to find the length of that dashed line or the width of rectangle 2.
12 ft - 11 ft = 1ft (width)
Length: 8 ft
Width: 1ft
A=l x w
A=8 x 1
A=8 ft^2
For Jordy to prove that ΔABE ≅ ΔBCD, at least one side in triangle ΔABE
should be congruent to the corresponding side in ΔBCD.
The correct option is choice B
- (B) <u>Jordy only established some of the necessary conditions for a congruency criterion</u>.
Reasons:
Statement
Reason
1∠BCD ≅ ∠ABE
1. Given
2. ∠CDB ≅ ∠BEA
2. Given
3.
3. Given
4. ∠CBD ≅ ∠BAE
4. Corresponding angles on parallel lines are congruent
5. <em>ΔABE ≅ ΔBCD </em>
<em> 5. Angle-angle-angle congruence</em>
<em />
The rules for congruency of two triangles are; SSS, SAS, ASA, AAS, and RHS.
The above acronyms stand for;
- SSS: Side-Side-Side congruency postulate; The three sides of each triangle are congruent
- SAS: Side-Angle-Side congruency postulate; Two sides and an included angle in one triangle are congruent to two sides and an included angle in another triangle.
- ASA: Angle-Side-Angle congruency postulate; Two angles and an included side are congruent in both triangles.
- AAS: Angle-Angle-Side congruency postulate; Two angles and a non included side are congruent in both triangles.
- RHS: The hypotenuse and one side in two right triangles are congruent
Therefore;
Jordy only established the congruency of the angles which are some of
the necessary conditions for congruency criterion. A side in ΔABE should
also be congruent to a corresponding side in ΔBCD in order to complete
the criteria for congruency.
Learn more about congruency rules here:
brainly.com/question/2292380