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Rufina [12.5K]
4 years ago
6

Josh wants to buy enough fruit punch for each guest at his birthday party to

Mathematics
2 answers:
Nikolay [14]4 years ago
6 0

Answer:

C. 9

Step-by-step explanation:

He is going to have 12 people including himself, and each is going to have 750 mL

12*750

9000 mL

There are 1000 mL in each liter, so divide 9000 by 1000

9000/1000=9

So he needs to buy 9, 1 liter containers of fruit punch

Hope this helps :)

sweet-ann [11.9K]3 years ago
3 0
1L = 1000mL

750/ 1000 = .75L

.75L x 12 people = 9L

So you need 9 1-liter containers of fruit punch
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Hey, your answer is d) 60cm
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What is the answer of this 5-x=7-2x
shtirl [24]

Answer:

x = 2

Step-by-step explanation:

5 - x  = 7 - 2x

-x + 2x = 7 - 5

x = 2

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Which of the following coordinates is a solution to the linear equation?
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Right this is pretty simple all you do is sub the points to the equation given.
So first try the first point (2,-1) in y=-3x+7
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Finally try the last points to make sure you are correct.
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3 years ago
A migrating bird flies 420 miles in 14 hours how many miles does it fly in 5 hours
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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
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