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AlexFokin [52]
3 years ago
9

L

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0
The answer to this question is 50
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3x^2 -5x -2=0
Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

3x = -1                   x = 2

x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

6 0
4 years ago
Read 2 more answers
Vertical angles must : check all that apply
trapecia [35]

Answer: B and C

Step-by-step explanation: For A, vertical angles can be complimentary or supplementary. For D, vertical angles can sometimes be acute but not always.

3 0
2 years ago
Read 2 more answers
The table shows the heights of students in a group.
Deffense [45]

Answer:

2.) 48 Inches

Step-by-step explanation:

Mean = average so to find the average you add all the numbers together and divide by the number of subjects there are so -

49 + 47 + 46 + 45 + 53 = 240

240 ÷ 5 = 48 in

have a good day! :)

6 0
3 years ago
Find the value of the following expression:
Misha Larkins [42]
(2^8*3^{-5}*6^0)^{-2}*( \cfrac{3^{-2}}{2^3} )^4*2^{28}\\ \\\\ = (\cfrac{2^8}{3^5}*1)^{-2} *( \cfrac{1}{3^2*2^3} )^4*2^{28}\\\\\\=( \cfrac{3^5}{2^8} )^2* \cfrac{1^4}{3^{2*4}*2^{3*4}} *2^{28}\\\\\\= \cfrac{3^{5*2}}{2^{8*2}} * \cfrac{1}{3^8*2^{12}} *2^{28}\\\\\\=\cfrac{3^{10}}{2^{16}} * \cfrac{2^{28}}{3^8*2^{12}}\\\\\\= \cfrac{3^{10}*2^{28}}{3^8*2^{16+12}} \\\\\\=\cfrac{3^{10}*2^{28}}{3^8*2^{28}} \\\\=3^{10-8}*2^{28-28}\\\\=3^2*2^0\\\\=9*1\\\\=9
3 0
4 years ago
Read 2 more answers
KLA=120x KLM=168x ALM=48. Find x
kakasveta [241]

Answer:

Step-by-st

respond  poorfa

7 0
3 years ago
Read 2 more answers
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