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Dmitry [639]
3 years ago
15

What is 9/32 + 7/8 plz help

Mathematics
2 answers:
Furkat [3]3 years ago
4 0

Answer:

1 5/32

Step-by-step explanation:

First, find common denominators. What you do to the denominator, you must do to the numerator.

First, multiply 4 to both the numerator and denominator of the second fraction:

(7/8)(4/4) = (7 * 4)/(8 * 4) = 28/32

Next, add across:

9/32 + 28/32 = 37/32

Simplify. Turn the improper fraction into a mixed fraction:

37/32 = (32 + 5)/32 = 1 5/32

1 5/32 is your answer.

~

stepan [7]3 years ago
3 0

Answer:

37 /32

Step-by-step explanation:

Find the least common denominator or LCM of the two denominators:

LCM of 8 and 32 is 32

For the 1st fraction, since 8 × 4 = 32,

7 /8  =  7 × 4

       8 × 4 =  28 /32

Likewise, for the 2nd fraction, since 32 × 1 = 32,

9 /32  =  9 × 1

          32 × 1 =  9 /32

Add the two fractions:

28 /32 +  9/32 =  28 + 9 /32  =  37 /32

So, 7/8 + 9/32 = 37/32

In mixed form: 1 5 /32

Please mark as brainliest!

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Let u and v be the solutions to 3x^2 + 5x + 7 = 0. Find u/v+v/u
Hitman42 [59]

Answer:   \dfrac{-17}{21}

Step-by-step explanation:

Given: u and v be are the solutions of  3x^2+5x+7=0

Let  ax^2+bx+c=0 is the quadratic equation and u and v are the zeroes/solutions then

Sum of zeroes;   u+v = \dfrac{-b}{a}

Product of zeroes; uv= \dfrac{c}{a}

Comparing  3x^2+5x+7=0  to  ax^2+bx+c=0

we get a= 3 , b= 5 and c = 7

u+v = \dfrac{-b}{a} = \dfrac{-5}{3}----(i)

uv= \dfrac{c}{a} = \dfrac{7}{3}----(ii)

Now we have to find

\dfrac{u}{v} +\dfrac{v}{u} =\dfrac{u^2+v^2}{uv} adding and subtracting 2uv in numerator we get

= \dfrac{u^2+v^2+2uv-2uv}{uv}= \dfrac{(u+v)^2-2uv}{uv}

Substituting the values from (i) and (ii) we get

\dfrac{(\dfrac{-5}{3} )^2-2\times \dfrac{7}{3} }{\dfrac{7}{3} } = \dfrac{\dfrac{25}{9} -\dfrac{14}{3} }{\dfrac{7}{3} }= \dfrac{\dfrac{25-42}{9} }{\dfrac{7}{3}} =\dfrac{-17}{9} \times \dfrac{3}{7} = \dfrac{-17}{21}

Hence, the value of \dfrac{u}{v} +\dfrac{v}{u}   is  \dfrac{-17}{21}

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