If the force between two charged objects when you triple the magnitude of both charges. The Force will become 9 times the initial force.
<h3>What is coulombs law?</h3>
According to coulombs law force between two charges is given by

Here, R is the distance between both the charges Q and q.
Let the force on the charges be F1
The distance of separation = r
The magnitudes of the charges q1 and q2
K = Coulumb's constant

Let the force on the charges be F
The distance of separation = r
The magnitudes of the charges 3q1 and 3q2
K = Coulumb's constant
So,


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Answer:
If i am correct,
f(4) = -8
g(-3) = 39
Step-by-step explanation:
H(x)=-16t^2+300
The average rate is the change in h divided by the change in t, mathematically:
r=(h(3)-h(0))/(t2-t1), in this case:
r=(-16*9+300-0-300)/(3-0)
r=-144/3
r= -48 ft/s
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