1st problem:
Use the Pythagorean theorem:
a^2+b^2=c^2
49+361=c^2
c^2=410
c=20.24
The answer is 20m
2nd problem:
First calculate the height using the Pythagorean theorem:
a^2+b^2=c^2
20^2+b^2=625 (i got 20 {radius} by half-ing the base edge length)
400+b^2=625
b^2=225
b=15
Next, solve for the volume:
V=a^2*h/3
V=40^2*15/3
V=1600*5
V=8000
The answer is the second choice or B.
Answer:
408.2sq inches
Step-by-step explanation:
Area of the cylindrical box = 2πr(r+h)
r is the radius = diameter/2
r = 10/2 = 5in
h is the height = 8in
Substitute
Area of the cylindrical box = 2(3.14)(5)(5+8)
Area of the cylindrical box = 2 * 3.14 * 5 * 13
Area of the cylindrical box = 408.2sq inches
Answer:
Step-by-step explanation:
The radius r can be found from the relationship
The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.
See the attached image.
divide total bags by number of hours
30 bags / 3 hors = 10 bags per hour
he racked 10 bags per hour
