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3 years ago

Which algebraic expression is equivalent to the expression below?

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

Answer:

I guess the answer is D - 18x + 18

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Anyone have these or know them???

horsena [70]

The answer would be y = 6x.

The reason for this is that when we add a number in front of x, it makes it go up vertically by the factor of that number. So if we are to stretch the graph vertically, the only way we can do it is by making 6 the coefficient.

8 0

3 years ago

Students were packed shoulder to shoulder in a gym for a pep rally. The students were in a rectangular shaped area of 7,500 ft2.

hram777 [196]

Answer: 1527

Step-by-step explanation:

Total Area = 7500 ft^2

Area covered by one student = Area of one circle

= π*r^2

r = radius of circle = 2.5/2 = 1.25 ft

Area covered by one student = π*1.25^2 = 4.91 ft^2

Number of students who can fit into total area = Total Area/Area covered by one student

Number of students who can fit into total area = 7500/4.91 = 1527.49

Hence the answer is 1527 students

7 0

3 years ago

Find the slope of the line that goes through (5,-8) and (-2,2)

saveliy_v [14]

Answer:

-1.42857

Step-by-step explanation:

3 0

3 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick different colors in the first four pick.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

3 years ago

Setenta y tres menos veintitrés es Noventa Cincuenta Cuarenta Ochenta

riadik2000 [5.3K]

cincuenta

73-23=50

hope it helps

6 0

3 years ago

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