Metals are the majority of the periodic table. Also, they are on the left side of the periodic table. The no metals are on the right side of periodic table.
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Answer:
Option A
They are located near the equator
Explanation:
From the diagram, we can observe that all the rain forest zones occur near the equator.
This is because on an annual basis, the equator receives the highest concentration of solar radiation in the whole Earth. This implies that the rate of evaporation of water from the water bodies present is high, and consequently, the amount of rainfall is high also. This abundant sunshine and high rainfall leads to the growth of the tropical rain forests at those regions
Answer:
Some common compounds in our daily lives:
Water, H2O. We need this for survival, because it serves a lot of functions in our body, such as being a medium for chemical reactions in our cells.
Carbon Dioxide, CO2. It is one of the components of air, our body also produces CO2 during respiration.
Sodium chloride, NaCl. Table salt is mostly made of sodium chloride. It is also found dissolved in sea water.
Methane, C2H4. This is a common fuel for generating electricity. It can also be found (small amounts) in air.
Nitrogen Dioxide, NO2. It can also be found in air, and it is one of the common air pollutants brought by burning of fossil fuels.
Answer:
Boiling point: 63.3°C
Freezing point: -66.2°C.
Explanation:
The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:
<em>Boiling point increasing:</em>
ΔT = kb*m*i
<em>Freezing point depression:</em>
ΔT = kf*m*i
ΔT are the °C that change boiling or freezing point.
m is molality of the solution (moles / kg)
And i is Van't Hoff factor (1 for I₂ in chloroform)
Molality of 50.3g of I₂ in 350g of chloroform is:
50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:
0.198 moles / 0.350kg = 0.566m
Replacing:
<em>Boiling point:</em>
ΔT = kb*m*i
ΔT = 3.63°C/m*0.566m*1
ΔT = 2.1°C
As boiling point of pure substance is 61.2°C, boiling point of the solution is:
61.2°C + 2.1°C = 63.3°C
<em>Freezing point:</em>
ΔT = kf*m*i
ΔT = 4.70°C/m*0.566m*1
ΔT = 2.7°C
As freezing point is -63.5°C, the freezing point of the solution is:
-63.5°C - 2.7°C = -66.2°C
