It would be 18 electrons i think
Hi there.
Alkali metals are known as the group 1 elements.
When we know this, we just have to look to group 1 of the periodic table.
Rb (Rubidium) is in group 1; it is classified as an alkali metal.
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Answer:
Explanation:
In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g
Let volume of given concentration of .12 g / ml required be V
In volume V , gram of iodine = V x .12 g
According to question
V x .12 = 9 g
V = 9 / .12 = 75 ml
So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .
Negative enthalpy change and positive entropy change. I am sure that's the answer!
