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Luden [163]
3 years ago
6

Can anybody help me? What is Oxidation? I used google but it didn't give me a good answer...

Chemistry
1 answer:
tino4ka555 [31]3 years ago
4 0
Oxidation is the loss of electrons and it also means adding oxygen,
you can memorise OILRIG which basically means Oxidation Is Loss of electrons while Reduction Is Gain of electrons.
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The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o
meriva

Answer:

\boxed{-267.5}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹   219.5      205.0         213.6         69.9

\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}

3 0
3 years ago
A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.
Anna35 [415]

Answer:

5.56 × 10⁻⁸

Explanation:

Step 1: Given data

  • Concentration of the weak acid (Ca): 0.187 M
  • pH of the solution: 3.99

Step 2: Calculate the concentration of H⁺

We will use the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3.99 = 1.02 × 10⁻⁴ M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(1.02 \times 10^{-4})^{2} }{0.187} = 5.56 \times 10^{-8}

3 0
3 years ago
12a. How does the model of the volcano provide evidence for the cycling of Earth materials through the rock cycle?
Bond [772]

Answer:

lava is coming from the crust

Explanation:

volcano's explode with lava because the crust pushes it out

6 0
3 years ago
A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com
VLD [36.1K]

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

= 60.054204

X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

6 0
4 years ago
How many atoms are in 35.1 g of sodium chloride (NaCl) ?
hoa [83]

Answer:

I believe that there are 70.2

Explanation:

There are 2 atoms in sodium chloride so I x 35.1 by 2 and got 70.2

8 0
3 years ago
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