9/13 is the awnser for this problem have a good day
Answer:
the first one squares are rectangles
Step-by-step explanation:
Answer: C
Explanation: You first convert the mixed numbers into improper fractions ( including the ones inside and outside of the parentheses) Then, subtract the fractions inside of the parentheses. Then whatever you got, add it to the fraction that was outside of the parentheses.
(7^5/6 - 5^1/3) + 1^1/9
^
(47/6 - 16/3) + 10/9
^
5/2 + 10/9
65/18 = 3^11/18
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:

And for this case we can use the Sylow theorems, given by:
Let G a group of order
where p is a prime number, with
and p not divide m then:
1) 
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168