Answer: 9h+40 (C)
Step-by-step explanation: the answer is 9h+40 because $9/hr rate is dependent on how many hours she worked (h), so it would be multiplied. She earned $40 already, so it would be added. the correct expression would be 9h + 40, or c.
Answer:
Large umber is 11, small one 7
Step-by-step explanation:
11- 4 =7
7+11=18
Answer:
0
Step-by-step explanation:
-2+3/-7+6
o/-1
0
as slope is y2-y1/
x2-x1
To find the inverse, we swap the variables y and x, then solve for the new y.
3a.
Swapping the variables:
Solving for y:
The domain of this inverse is
.
3b.
Swapping:
Solving for y:
The domain of this inverse is
.
3c.
![y=\sqrt[3]{\frac{x-7}{3}}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D)
Swapping:
![x=\sqrt[3]{\frac{y-7}{3}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7By-7%7D%7B3%7D%7D)
Solving for y:
The domain of this inverse is all real numbers.
4a.
,
4c.
,
![y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%283x%5E3%2B7%29-7%7D%7B3%7D%7D%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3x%5E3%7D%7B3%7D%7D%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%20%5C%5C%20y%3Dx)
![y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x](https://tex.z-dn.net/?f=y%3D3%28%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D%29%5E3%2B7%20%5C%5C%20y%20%3D%203%28%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D%29%2B7%20%5C%5C%20y%20%3D%20%28x-7%29%2B7%20%5C%5C%20y%3Dx)
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.
Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).
In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.
Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.
Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.
The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
