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nlexa [21]
2 years ago
5

What is the difference between 0.02 and -0.02​

Mathematics
1 answer:
Degger [83]2 years ago
5 0

Answer:

0.04

Step-by-step explanation:

Using absolute value |.02|+|.-02|= .04

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Jill earned $40 from a carpool plus $9 per hour (h) babysitting this week. Which of the following expressions best represents Ji
Svetlanka [38]

Answer: 9h+40 (C)

Step-by-step explanation: the answer is 9h+40 because $9/hr rate is dependent on how many hours she worked (h), so it would be multiplied. She earned $40 already, so it would be added. the correct expression would be 9h + 40, or c.

4 0
3 years ago
This is for my sister
ELEN [110]

Answer:

Large umber is 11, small one 7

Step-by-step explanation:

11- 4 =7

7+11=18

5 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through<br> the points (-6, -2) and (-7, -2)
xxTIMURxx [149]

Answer:

0

Step-by-step explanation:

-2+3/-7+6

o/-1

0

as slope is y2-y1/

x2-x1

7 0
3 years ago
SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!
Shkiper50 [21]
To find the inverse, we swap the variables y and x, then solve for the new y.

3a. y=\frac{3}{x-1}

Swapping the variables: x=\frac{3}{y-1}
Solving for y: x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}
The domain of this inverse is x ≠ 0.
3b. y=x^2-1

Swapping: x = y^2 - 1
Solving for y: y^2 = x + 1 \\ y = \sqrt{x+1}
The domain of this inverse is x ≥ -1.
3c. y=\sqrt[3]{\frac{x-7}{3}}
Swapping: x=\sqrt[3]{\frac{y-7}{3}}
Solving for y: x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7
The domain of this inverse is all real numbers.
4a. y=\frac{3}{x-1}, y=1+\frac{3}{x}
y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x
y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x

4c. y=\sqrt[3]{\frac{x-7}{3}}, y=3x^3+7
y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x
y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x



3 0
3 years ago
There are 9 marbles representing 3 different colors. Write a problem where 2 marbles are selected at random without replcement a
Nata [24]
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.

Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).

In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.

Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.

Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.

The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
8 0
3 years ago
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