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fomenos
3 years ago
14

Write the first five terms of the sequence whose general term, an, is given an= - 5n + 8

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer: See Explanation

Step-by-step explanation:

1st term = an= - 5n + 8 = -5(1) + 8

= -5 + 8

a1 = 3

2nd term = an= - 5n + 8 = -5(2) + 8

= -10 + 8

= -2

3rd term = an= - 5n + 8 = -5(3) + 8

= -15 + 8

= -7

4th term = an= - 5n + 8 = -5(4) + 8

= -20 + 8

= -12

5th term = an= - 5n + 8 = -5(5) + 8

= -25 + 8

= -17

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A bakery sells one cupcake for $2.75 or a dozen cupcakes for $25.80. If you
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<em>D </em><em>$0.60</em>

Step-by-step explanation:

Since <em>a dozen is equal to 12</em>, we will first <em>multiply $2.75 by 12</em>, and we get <em>$33</em>.  Now <em>subtract $33 by $25.80</em> dollars, which is <em>$7.2.</em>  Now we know that we saved <em>$7.2 </em>out of a dozen cupcake's, but we have to find <em>how much we saved on </em><u><em>each</em></u><em> cupcake</em>.  So lets <em>divide $7.2 by 12</em> and we get <em>$0.60. </em> Therefore, you saved <em>$0.60</em> on each cupcake.

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A particular brand of dishwasher soap is sold in three sizes: 25 oz, 45 oz, and 60 oz. Twenty percent of all purchasers select a
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Answer:

(a) <u>Sampling distribution </u>

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P(45) = 0,25

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Step-by-step explanation:

The variable we want to compute is

X=(X1+X2)/2

For this we need to know all the possible combinations of X1 and X2 and the probability associated with them.

(a) <u>Sampling distribution </u>

Calculating all the 9 combinations (3 repeated, so we end up with 6 unique combinations):

P(25) = P(X1=25) * P(X2=25) = p25*p25 = 0.2 * 0.2 = 0,04

P(35) = p25*p45+p45*p25 = 0.2*0.5 + 0.5*0.2 = 0.1 + 0.1 = 0,2

P(42,5) = p25*p60 + p60*p25 = 0.2*0.3 + 0.3*0.2 = 0.06 + 0.06 = 0,12

P(45) = p45*p45 = 0.5 * 0.5 = 0,25

P(52,5) = p45*p60 + p60*p45 = 0.5*0.3 + 0.3*0.5 = 0.15 + 0.15 = 0,3

P(60) = p60*p60 = 0.3*0.3 = 0,09

(b) Using the sample distribution, E(X) can be expressed as:

E(X)=\sum_{i=1}^{6}P_{i}*X_{i}\\E(X)=0.04*25+0.2*35+0.12*42.5+0.3*52.5+0.09*60 = 45.5

The value of E(X) is 45.5 oz.

(c) The value of μ can be calculated as

\mu=\sum_{i=1}^{3}P_{i}*X_{i}\\\mu=0.2*25+0.5*45+0.3*60=45.5

We can conclude that E(X)=μ

We could have arrived to this conclusion by applying

E(X)=E((X1+X2)/2)=E(X1)/2+E(X2)/2\\\\\mu = E(X1)=E(X2)\\\\E(X)=\mu /2+ \mu /2 = \mu

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Answer:

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