Solve this system of linear equations. Seperate the x- and y-values with a comma.

Mathematics

1 answer:

balu736 [363]3 years ago

6 0

The answer to the question

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Admission to a museum is $7.10 per

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kakasveta [241]

$\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}$

Explanation:

$\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}$ $\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}$ $\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}$

$\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}$ $\text{output = input + 5}$

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1 year ago

The sum of two numbers<br> is 8. their difference is 12.<br> find the numbers.

Aleonysh [2.5K]

X + y = 8
x - y = 12
--------------add
2x = 20
x = 20/2
x = 10

x + y = 8
10 + y = 8
y = 8 - 10
y = -2

ur numbers are 10 and -2

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3 years ago

Read 2 more answers

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Answer:

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