The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
<h3>Calculation of the total capital invested</h3>
The time the investment lasted= 12 years.
Simple interest = 1579.05 - 800= $779.05
The principal capital= $800
Rate of the both capital invested;
= SI × 100/P ×T
= 779.05 × 100/800 × 12
= 77,905/9600
= 8.11%
To find the amount of money that Phyllis invested at each given rate,
Rate 1 = 4/8.11× 800
= 3200/8.11
= $394.57
Rate 2 = 6/8.11× 800
= 4800/8.11
= $591.86
The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
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To solve this we would do 30×365
We would do this because each day the dog 30lbs
So we have the equation y=30x
Where y= total amount of dog food
And x= number of days
In a year there are 365 days typically, so we do 30×365
30×365=10,950
In one year 10,950 lbs of dog food are used
Answer:
the answer would be no solution
Step-by-step explanation:
because, Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation
3/4y-(5/x)=0
and from there you may not do anything else.
Answer:
The sum of the money shared is $1372
Step-by-step explanation:
The given ratio is
Albert:Michael:Moses=3:5:6
The total ratio is 3+5+6=14
Let the sum of money shared be $x.
Then Albert's share = 3/14 x 
= 3/ 14
Michal's Share = 5x/14
If Michael received $196 more than Albert, then the difference between their share is the $196.
Answer:
<h2>y - 5 = -1(x + 3)</h2>
Step-by-step explanation:
The point-slope form of an equation of a line:
m - slope
We have m = -1 and the point (-3, 5). Substitute:
