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Mekhanik [1.2K]
3 years ago
11

PLS HELP K12

Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

I may be wrong

Step-by-step explanation:

top left EE bottom left EH top right EH bottom right HH

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HELPPP KE PJEASE. ASAPPPP ITS FOR A QUIZZZ
san4es73 [151]
=(1/2) * 2 * 3.2 + (1/2) *2 * 3.2 + (1/2) * 2 * 4 + (1/2) * 2 * 4
= 2 * 3.2 + 2 * 4
= 2 * (3.2 + 4)
= 2 * 7.2
= 14.4 sq feet
2 * 14.4 = 28.8 sq feet
8 0
3 years ago
Can you help me with this...thank you​
mr_godi [17]
You solve by with by altitude! Hope it helps
3 0
3 years ago
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What is the common ratio of the geometric sequence below?<br> 18, -6, 2. - ...
pantera1 [17]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
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Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
3 years ago
Read 2 more answers
a circle is centered at the point -3,2) and passes through the point (1,5). The radius of the circle is blank units. The point (
lianna [129]
It's important that you share the complete question.  What is your goal here?  Double check to ensure that you have copied the entire problem correctly.

The general equation of a circle is x^2 + y^2 = r^2.  Here we know that the circle passes thru two points:  (-3,2) and (1,5).  Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.


Subst. the known values (of the first point) into this equation:  (-3)^2 + (2)^2 = r^2.  Then 9 + 4 = 13 = r^2.

Let's check this.  Assuming that the equation of this specific circle is 
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.

(1)^2 + (5)^2 = 13 is not true, unfortunately.

(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).

Check the original problem.  If it's different from that which you have shared, share the correct version and come back here for further help.



3 0
3 years ago
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