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Julli [10]
3 years ago
9

The circumference of a circle is 314 units. What is the area?

Mathematics
1 answer:
german3 years ago
4 0

Answer:

7850 square units

Step-by-step explanation:

According to the question;

  • Circumference of a circle is 314 units;

We are required to find the area of the circle;

  • First, we need to ask ourselves how we get the perimeter of a circle;

Perimeter of a circle = pi × D or 2 pi r

Therefore;

Rearranging the formula;

D = Perimeter ÷ pi

Taking pi to be 3.14

Then;

Diameter = 314 units ÷ 3.14

              = 100 units

But, radius = Diameter ÷ 2

                  = 100 units ÷ 2

                  = 50 units

We also need to know how we calculate the area of a circle;

Area of a circle = pi×r²

Therefore;

Taking pi as 3.14

Then, Area = 3.14 × 50²

                   = 7850 square units

Thus, the area of the circle is 7850 square units

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Makovka662 [10]
Let the number be x.

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x = -(7/8)/-(3/4)

x = 7/8 * 4/3

x = 7/6

The number = 7/6
4 0
3 years ago
Gretta has a savings account with $6,500 in it that earns 9.5% simple interest per year. How much interest, to the nearest cent,
meriva

Answer: $617.50

Step-by-step explanation:

9.5% of 6500 = 9.5*6500/100=9.5*65=617.5

So the interest is $617.5 or $617.50

Hope this helped. If you have any questions or clarifications please ask.

Thanks and please rate!

6 0
1 year ago
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A jar contains 4 red and 8 blue marbles a marble is drawn from the jar what is the probability that a red marble is drawn ?
frosja888 [35]

There is a 1/3 chance that a red marble would be chosen.

To find out you put add up the marbles, so they will make 12 marbles.

Since there are 4 red you put 4/12.

4/12 simplified is 1/3.

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5 0
3 years ago
Pls help I really need help pls I need Profesional at math pls pls ​
Rzqust [24]

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RIP OFFFFFFF

THE SECOND ONE IS A WAY BETTER OF A DEAL

4 0
2 years ago
Find in degrees the numeric value of the acute angle of rotation that eliminates the product term from the equation 7x2+24xy−34x
lutik1710 [3]

Rotating the graph of Ax^2+Bxy+Cy^2+Dx+Ey+F=0 with B\ne0 counterclockwise by \theta eliminates the xy term, where \cot2\theta=\frac{A-C}{B}. Plugging in, we have \cot2\theta=\frac{7}{24}, since C=0. Solving, we have \theta=\frac{1}{2}\cot^{-1}(\frac{7}{24})\approx\boxed{36.9^\circ}.

4 0
3 years ago
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