The diagram below represents the creation of a sugar solution by adding sugar to water then stirring the mixture.

2.4 moles of NO, 2.4 moles of Oz, and 2.4 moles of H2O react

Len [333]

Answer:

83%

Explanation:

2.4 moles of NO, 2.4 moles of O2, and 2.4 moles of H2O react to form 2.0 moles of HNO3. What is the percent yield of this reaction? ___ % 83.

7 0

4 years ago

A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely

Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

$N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)$

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

$P_{total}=P_{NO_{2}}+P_{NO}$

we don't include $N_{2}O_{3}$ because it decomposed completely.

Assuming ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of $N_{2}O_{3}$ is:

$n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}$

from the reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of $N_{2}O_{3}$ .

$n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}$

$n_{NO}=\frac{P_{1}V}{RT_{1}}$

The partial pressure of each gas is:

$P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}$

$P_{NO}=\frac{n_{NO}*R*T_{2}}{V}$

so total pressure is:

$P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}$

replacing the moles we get:

$P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}$

We know that T2=3*T1

replacing this value in the equation we get:

$P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}$

$P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm$

5 0

4 years ago

In which of the following cases will the LEAST time be required to arrive at equilibrium? K below refers to the equilibrium cons

mylen [45]

Answer: Option (4) is the correct answer.

Explanation:

It is known that equilibrium constant is represented as follows for any general reaction.

$A + B \rightarrow C + D$

K = $\frac{[C][D]}{[A][B]}$

As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.

As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.

Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.

8 0

3 years ago

4. (He] 2s^1 2p^4 is the correct electron configuration for:<br> a) C<br> b) O<br> c) Si<br> d) S

Aleksandr-060686 [28]

Hey there!

[He]2s²2p⁴ is the electron configuration for O (oxygen).

He is the noble has before oxygen. It has 2 electrons.

The s orbital is filled, and there are 4 electrons in the p orbital, so 6 elements over to the right.

This makes a total of 8 electrons.

Hope this helps!

8 0

4 years ago

Elemental sulfur occurs as octatomic molecules, S₈. What mass (g) of fluorine gas is needed to react completely with 17.8 g of s

Fed [463]

Elemental sulfur occurs as octatomic molecules, 63.2 g F2 are needed to react completely with 17.8 g S8 to produce SF6 .

<h3>What is octatomic molecules?</h3>

When stable under normal temperature and pressure circumstances, an octatomic element is a chemical element that has eight atoms arranged in a group. Sulfur, symbol S8, is the classic example, but red selenium is also an octatomic element that is stable at ambient temperature.

A molecule with eight sulfur atoms has a puckered ring or crown structure. Sulfur is in an octet state when it contains two more electrons than the six in its outermost shell. Sulfur has an atomic number of 16 and an electrical configuration of 2, 8, 6.

Other elements (S, Se, and Te) exist as octatomic solids while oxygen is a diatomic gas at normal temperature.

To learn more about octatomic molecules from the given link:

brainly.com/question/23921436

#SPJ4

7 0

2 years ago