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ch4aika [34]
2 years ago
14

In which of the following cases will the LEAST time be required to arrive at equilibrium? K below refers to the equilibrium cons

tant.1. Cannot tell since the time to arrive at equilibrium does not depend on K.2. K is a very large number.3. K is about 1.4. K is a very small number.5. Cannot tell without knowing the value of K.
Chemistry
1 answer:
mylen [45]2 years ago
8 0

Answer: Option (4) is the correct answer.

Explanation:

It is known that equilibrium constant is represented as follows for any general reaction.

                 A + B \rightarrow C + D

                   K = \frac{[C][D]}{[A][B]}

As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.

As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.

Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.

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When 8.0 moles of methanol are reacted with 9.0 moles of oxygen, how many moles of water vapor does the reaction produce?
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Answer:

12 moles of H₂O are formed in this combustion.

Explanation:

First of all, think the reaction:

2CH₃OH (l) +  3O₂ (g) →  2CO₂ (g) + 4H₂O (g)

Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂

We have 9 moles of O₂, so this is the limiting reactant.

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Then, 9 mol of oxygen will produce ( 9 .4)/3 = 12 moles

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Explanation:

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So, by increasing the turns and increasing current flowing through wire one can increase the strength of an electromagnet.

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