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ki77a [65]
3 years ago
8

4. (He] 2s^1 2p^4 is the correct electron configuration for: a) C b) O c) Si d) S

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Hey there!

[He]2s²2p⁴ is the electron configuration for O (oxygen).

He is the noble has before oxygen. It has 2 electrons.

The s orbital is filled, and there are 4 electrons in the p orbital, so 6 elements over to the right.

This makes a total of 8 electrons.

Hope this helps!

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Explanation:

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An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm
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The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

 xA= 0.34, yA= 0.55

ii)      0.50 = 0.55 nv + 0.34 nL

     Therefore, nV =    0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii)  ρA= 0.791 g/cm3 and,  ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

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5 0
4 years ago
Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd
d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

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Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

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Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

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0.1863\ mole= \frac{Mass}{4.0026\ g/mol}

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<u>0.7457 g is the mass of the helium gas. </u>

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