Replacement reaction because one element takes place of another element in a compound.
<span>Answer:
CuX = Cu2+ + X2-
Ksp = [Cu2+] * [X2-]
for each mole of CuX that dissolves we get x mol of each of the anions and cations
Ksp = x^2 = 1.27 x 10 ^-36
x= 1.13 x 10 ^-18 moles of CuX per liter of pure water
if the solution has [Cu2+]= 0.27 M
Ksp becomes x ( x + 0.27)
as we can see above x is extremely small so can be ignored inside the brackets
0.27 x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.27 = 4.70 x 10 ^-36 moles per liter
In 0.19M X2- we have
Ksp = 0.19x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.19 = 6.68 x 10 ^-36 moles per liter</span>
Is an acid. Methyl red is a pH indicator that changes color indicating acid.
The state of the balloon:
When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.
What is Osmosis:
Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.
<u><em>Hypertonic solution:</em></u>
It means that there are more solutes present in the surrounding environment than in the cell itself.
<u><em>Hypotonic solution:</em></u>
In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.
- When comparing two solutions, the one with the larger solute concentration is hypertonic, and the one with the lower solute concentration is hypotonic. Isotonic solutions have an identical solute concentration.
- While the solution in the beaker is hypertonic, Meaning that will draw water molecules out of the cell. As water molecules move from a location of high water potential (dilute solution) to a region of reduced water potential (10% glucose solution), the water from the 5% glucose solution will flow into the 10% one (concentrated solution)
- This is the reason why the amount of water decreases when the balloon is submerged in the beaker.
Learn more about the glucose solution and permeability here,
brainly.com/question/14748422
#SPJ4
<u>Answer:</u> C) be hypertonic to Tank B.
<u>Explanation: </u>
<u>
The ability of an extracellular solution to move water in or out of a cell by osmosis</u> is known as its tonicity. Additionally, the tonicity of a solution is related to its osmolarity, which is the <u>total concentration of all the solutes in the solution.
</u>
Three terms (hypothonic, isotonic and hypertonic) are used <u>to compare the osmolarity of a solution with respect to the osmolarity of the liquid that is found after the membrane</u>. When we use these terms, we only take into account solutes that can not cross the membrane, which in this case are minerals.
- If the liquid in tank A has a lower osmolarity (<u>lower concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypotonic with respect to the latter.
- If the liquid in tank A has a greater osmolarity (<u>higher concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypertonic with respect to the latter.
- If the liquid in tank A has the same osmolarity (<u>equal concentration of solute</u>) as the liquid in tank B, the liquid in tank A would be isotonic with respect to the latter.
In the case of the problem, option A is impossible because the minerals can not cross the membrane, since it is permeable to water only. There is no way that the concentration of minerals decreases in tank A, so <u>the solution in this tank can not be hypotonic with respect to the one in Tank B. </u>
Equally, both solutions can not be isotonic and neither we can say that the solution in tank A has more minerals that the one in tank B because the liquid present in tank B is purified water that should not have minerals. Therefore, <u>options B and D are also not correct.</u>
Finally, the correct option is C, since in the purification procedure the water is extracted from the solution in tank A to obtain a greater quantity of purified water in tank B. In this way, the solution in Tank A would be hypertonic to Tank B.
