Given :
Distance covered by object , D = 63 cm .
Time taken to cover distance D , t = 2 days .
To Find :
The speed of object in m/s .
Solution :
First we will convert all units into m and hours .
D = 63 cm = 0.63 m .
.
Now , speed is :

Hence , this is the required solution .
Answer:


Step-by-step explanation:
Given


Required
Solve by elimination
To do this, we subtract both equations (to eliminate x)

- 
--------------------


Substitute
in 

Solve for 3x

Solve for x


The percent change between the temperature at noon and the temperature at 5:00 p.m. is -20%
The percent change is the relative change between two quantities expressed in percentage.
Given that the At noon, the temperature was 80°F while At 5:00 p.m., the temperature was 64°F. Hence:
Percent change = [(64°F - 80°F) / 80°F] * 100%
Percent change = -20%
Therefore the percent change between the temperature at noon and the temperature at 5:00 p.m. is -20%
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Answer:
I am not sure if my math is correct but I got $15 dollars in change.
Step-by-step explanation:
$50 times 0.10 (10%) equals $5. $50.00 minus $30.00 is $20.00. $20 minus $5 is $15.