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kherson [118]
3 years ago
8

A person is standing exactly 36 ft from a telephone pole. there is a 30° angle of elevation from the ground to the top of the po

le. what is the height of the pole? 12 ft ft 18 ft ft

Mathematics
2 answers:
IrinaVladis [17]3 years ago
6 0
I believe option B ... 12 (square root of) 3 ft
Bond [772]3 years ago
4 0

Answer:

As per the statement:

A person is standing exactly 36 ft from a telephone pole. there is a 30° angle of elevation from the ground to the top of the pole.

⇒Distance of a person from the telephone pole = 36 ft.

and angle of elevation ( \theta) = 30 degree.

We have to find the height of the pole.

Let h be the height of the pole.

Using tangent ratio:

\tan \theta = \frac{\text{opposite side}}{\text{adjacent side}}

Here,

Opposite side = h foot

Adjacent side = 36 ft

Angle of elevation: \theta = 30^{\circ}

Substitute these to solve for AB:

\tan 30^{\circ} = \frac{h}{36}

or

h = 36\cdot \tan 30^{\circ}

or

h = 36\cdot \frac{1}{\sqrt{3}}

Simplify:

h = 12\sqrt{3} ft

Therefore, the height of the pole is 12\sqrt{3} ft

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