A. the value of the function will approach zero as the value of x gets very large.
b. when x=0, the function is undefined, because 1/x is a fraction and the denominator of a fraction cannot be zero.
D bc you distribute the 2 to both numbers first and that takes up 2 letter F O
We are not dum because it’s hanging
<h2>
Answer with explanation:</h2>
Given : A standardized exam's scores are normally distributed.
Mean test score : ![\mu=1490](https://tex.z-dn.net/?f=%5Cmu%3D1490%20)
Standard deviation : ![\sigma=320](https://tex.z-dn.net/?f=%5Csigma%3D320)
Let x be the random variable that represents the scores of students .
z-score : ![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .
For x= 1900
![z=\dfrac{1900-1490}{320}\approx1.28](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B1900-1490%7D%7B320%7D%5Capprox1.28)
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 1240
![z=\dfrac{1240-1490}{320}\approx-0.78](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B1240-1490%7D%7B320%7D%5Capprox-0.78)
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 2190
![z=\dfrac{2190-1490}{320}\approx2.19](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B2190-1490%7D%7B320%7D%5Capprox2.19)
Since it is greater than 1.96 , thus it is unusual.
For x= 1240
![z=\dfrac{1370-1490}{320}\approx-0.38](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B1370-1490%7D%7B320%7D%5Capprox-0.38)
Since it lies between -1.96 and 1.96 , thus it is not unusual.
19. 38x - 3y - 34 because 5(7x+3y-8) =!35x+15y-40 and 3(x-6y+2 = 3x -18y +6. Combine alike factors.
20. Yes it is factored correctly.