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Nataliya [291]
3 years ago
5

A total of 6 family members will appear in a portrait. if 2 of the family members may sit in the front row how many combinations

of family
members may sit in the front row?
Mathematics
2 answers:
Kobotan [32]3 years ago
8 0
A total of six family members will appear in a portrait and two of the family members may sit in the front row, there will be fifteen combinations of family members that may sit in the front row.
liq [111]3 years ago
4 0

There will be a total if 15 combinations of family members that can sit in the back.

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You earned 90% on a science quiz. You answered 27 questions correctly. How many questions were on the test?
Scilla [17]

Answer:

There were 30 questions on the test.

Step-by-step explanation:

1. Set up your equation: 27/90 = y/100

2. Next you want to cross multiply: 2700 = 90y or 270 = 9y

3. Divide 270 by 9 to find your y: y = 30

There were 30 questions on the test.

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3 years ago
A linear function has a slope of -7/9 and a y-intercept of 3. How does this function compare to the linear function that is repr
Dmitriy789 [7]
The answer is that they're equal, one is just in point-slope form and the other is in slope-intercept form
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A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly
shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}

P(First\ White) = \dfrac{3}{10}

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

4 0
3 years ago
Plz help i will mark brainliest
Stels [109]

Answer:

43

Step-by-step explanation:

5 0
3 years ago
0.017, 0.2, 0.02, 0.007
xxMikexx [17]
I have know idea sorry u don’t know this their isn’t any explanation
6 0
3 years ago
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