Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
20 because radius times height will give you the surface area of the shape
Answer:
A = a + b / 2 x h
Step-by-step explanation:
Area is equal to side one plus side two divided by two then you multiply by the height of the trapezoid. Hope this helps!
I’m pretty sure they’re collinear. I’m so sorry if I’m wrong.
Answer:
the one on the right y=4x
Step-by-step explanation:
even if u switch out x it will yeah
