Question

Can someone do this fast ? I need it for tomorrow

Answer 1

Answer:

Step-by-step explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to $3x^2+x-1$.

hg(x) = $x^2(x+2)$ which simplifies to

$x^3+2x^2$. Now set that equal to $3x^2+x-1$:

$x^3+2x^2=3x^2+x-1$ and get everything on the same side and factor:

$x^3-x^2-x+1=0$. Factor by grouping:

$(x^3-x^2)-(x+1)=0$ and factor out what's common in each set of ( ):

$x^2(x-1)-1(x-1)=0$ which factors out to

$(x^2-1)(x-1)=0$. But $x^2-1$ factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1