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leonid [27]
2 years ago
5

Can someone do this fast ? I need it for tomorrow

Mathematics
1 answer:
gregori [183]2 years ago
7 0

Answer:

Step-by-step explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to 3x^2+x-1.

hg(x) = x^2(x+2) which simplifies to

x^3+2x^2. Now set that equal to 3x^2+x-1:

x^3+2x^2=3x^2+x-1 and get everything on the same side and factor:

x^3-x^2-x+1=0. Factor by grouping:

(x^3-x^2)-(x+1)=0 and factor out what's common in each set of ( ):

x^2(x-1)-1(x-1)=0 which factors out to

(x^2-1)(x-1)=0. But x^2-1 factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1

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