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3 years ago

8

Troy and two of his friends do yard work after school. After paying $35 for gas and supplies, the boys made $128 dollars. How mu

ch will each boy make?

1 answer:

Allisa [31]3 years ago

5 0

Answer:

$54.33

Step-by-step explanation:

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Helpppppppppppppppppp

makkiz [27]

For this case we have the following system of equations:

$8x-9y = -122\\-8x-6y = -28$

To solve, we add both equations:

$8x-8x-9y-6y = -122-28\\-15y = -150\\y = \frac {-150} {- 15}\\y = 10$

We find the value of "x":

$8x = -122 + 9y\\x = \frac {-122 + 9y} {8}\\x = \frac {-122 + 9 (10)} {8}\\x = \frac {-122 + 90} {8}\\x = \frac {-32} {8}\\x = -4$

The solution is (-4,10)

ANswer:

Option C

5 0

3 years ago

Tonya is saving money to buy a computer that costs $375. She has saved $75 already and each week she adds $25 to her savings. Ho

schepotkina [342]

It will take her 12 weeks if she saves the money she gets per week
Since the price of the computer is $375 and she already has $75 dollars saved she only needs $300 more to buy the computer.
She gets $25 per week so she it will take (25/300) weeks for to buy the computer
so that simplifies into 12 weeks
therefore it will take her 12 weeks to buy her computer

7 0

3 years ago

Here are the prices for cans of juice that are the same brand and the same size at different stores. Which store offers the best

Hitman42 [59]

Answer:

Store Z

Step-by-step explanation:

Store X: 4 cans for $2.48, so 2.48/4= $0.62 per can

Store Y: 5 cans for $3.00, so 3.00/5= $0.60 per can

Store Z: $0.59 per can

Store Z offers the best deals since it cost less than the other

8 0

3 years ago

Read 2 more answers

Which of the following is the best description of the graph below?

Alinara [238K]

full question

there are no graphs

3 0

3 years ago

Read 2 more answers

The sample loses 1/3of it’s mass every ___ days

eimsori [14]

Answer:

The sample loses $\frac{1}{3}$ of its mass every $\frac{1}{3}$ days.

Step-by-step explanation:

Expression that shows the relation between final mass of the element after 't' days is,

M(t) = $900(\frac{8}{27})^t$

If M(t) = two third of the initial mass [After the loss of one third of the initial mass remaining mass of the element = 1 - $\frac{1}{3}$ = $\frac{2}{3}$ rd of the initial mass]

$900\times \frac{2}{3}=900(\frac{8}{27})^t$

$\frac{2}{3}=(\frac{8}{27})^t$

$\frac{2}{3}=[(\frac{2}{3})^3]^t$

$(\frac{2}{3})^1=(\frac{2}{3})^{3t}$

By comparing powers on both the sides

3t = 1

t = $\frac{1}{3}$ day

Therefore, The sample loses $\frac{1}{3}$ of its mass every $\frac{1}{3}$ days.

5 0

3 years ago