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2 years ago

Status

Mathematics

1 answer:

blsea [12.9K]2 years ago

5 0

Answer:

y = -2x - 1

Step-by-step explanation:

y + 3 = -2 ( x - 1 )

y + 3 = -2x + 2

y = -2x - 1

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The temperature was 2.5°C below zero. After 4 hours, the temperature was now 5.6°C

ELEN [110]

Answer:

3.1 degrees celcius

Step-by-step explanation:

5.6C-2.5C=3.1C

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3 years ago

Does tis table represent a function ?

frutty [35]

The answer is A. This can be seen in the table where y can be both 4 and 3 for when x = 3. In a function, an output can have more than one input, but an input can have have only one output.

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3 years ago

Read 2 more answers

A) The cosine rule can be used to find the value of x in the triangle below.

BartSMP [9]

Answer:

see explanation

Step-by-step explanation:

(a)

(the side required )² = sum of squares of other 2 sides - ( 2 × product of other 2 sides and cos(angle opposite side required ) )

x² = 12² + 15² - (2 × 12 × 15 × cos71°)

(b)

x² = 144 + 225 - 360cos71°

= 369 - 360cos71° ( take square root of both sides )

x = $\sqrt{369-360cos71}$

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5 0

1 year ago

Multiply (n+12)(n-7)

ki77a [65]

(n+12)(n-7) = n^2 + 5n - 84

8 0

3 years ago

Dy/dx = y/x , y(1) = −2

s2008m [1.1K]

Start with

$\dfrac{dy}{dx}=\dfrac{y}{x}$

Separate the variables:

$\dfrac{dy}{y} = \dfrac{dx}{x}$

Integrate both parts:

$\displaystyle \int \dfrac{dy}{y} = \int\dfrac{dx}{x}$

Which implies

$\log(y) = \log(x)+c$

Solving for y:

$y = e^{\log(x)+c} = e^{\log(x)}e^c=xe^c$

Since $e^c$ is itself a constant, let's rename it $c_1$ .

Fix the additive constant imposing the condition:

$y(1) = c_1\cdot 1 = -2\iff c_1=-2$

So, the solution is

$y(x) = -2x$

5 0

3 years ago