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Jet001 [13]
3 years ago
15

Plz Help... I am very stupid ​

Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Answer:

b

Step-by-step explanation:

It's b because if you plug in 1 for d in each of the equations, you get 99 in b only.

SpyIntel [72]3 years ago
4 0

Answer:

The answer is b.  f(d) = 11 × 9^{d}

Step-by-step explanation:

March 14 the video has 11 views

March 15 the video has 99 views

To get the number of views on second day:

f(d) = 11 × 9^{1}

So the equation of the function that will arrive at number of views in any particular day from March 14 is:

f(d) = 11 × 9^{d}

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What is 243 written as a power of a number?
Zigmanuir [339]
A to the power of b

a^b 

a = base

b = exponent

SO

10^243 or 10 to the power of 243.

You can use other numbers also.

Hope i helped!!  
8 0
3 years ago
PLEASE HELP!!!!<br>how to solve 9x^3-16x^2=0 by factoring<br> WILL GIVE BRAINLIEST IF CORRECT!!!!
andreev551 [17]

Answer:

x=5.3

Step-by-step explanation:

Graph each side of the equation. The solution is the x-value of the point of intersection.

x

≈

5.3

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7 0
2 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
2 years ago
The solution to the equation?
notsponge [240]
X=5
add like terms :)
5 0
3 years ago
Factor 15x^2y^2 - 3x^3y + 75x^4<br> Please show step by step explanation, thank you! &lt;3
sweet-ann [11.9K]

Answer:

3X^2(5y^2-3xy+25x^2)

Step-by-step explanation:

Factor by finding the GCF, Greatest Common Factor.

8 0
3 years ago
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