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Nikitich [7]
3 years ago
13

What is the equation of a line that goes through the point (0, -5) and has a slope of -3?

Mathematics
2 answers:
juin [17]3 years ago
8 0

Answer:

y = -3x - 5

Step-by-step explanation:

The equation of a line is given as either:

y = mx + b  where m is the slope, and b is the y-intercept.

or

y-y_{1} = m(x-x_{1} )  where given that you have a point (x, y), y₁ is the y-value of the point, m is the slope, and x₁ is the x-value of the point.

We can just plug in the point (0, -5) into the second equation and -3 for the slope.

<em>However,</em> (0, -5) tells us that this point must be a <u>y-intercept</u>, since the x-value of that point is 0. So, we can also just plug into the first equation -5 for the y-intercept and -3 for the slope.

So, we get:

y = -3x + (-5)

Which simplifies into:

y = -3x - 5

insens350 [35]3 years ago
8 0

Answer:

i dont know

Step-by-step explanation:

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HI can you help me with this question
dolphi86 [110]

Answer:

  42 square centimeters

Step-by-step explanation:

The total of sides FA and AB will be half the perimeter of the rectangle, or 14 cm. Since AB is 9 cm, that means FA is 5 cm.

EF is the difference between EF and FA, so is 11 cm -5 cm = 6 cm.

FC is the same 9 cm length as AB, so we have enough information about the trapezoid to use the area formula:

  A = (1/2)(b1 +b2)h

  A = (1/2)(9 cm +5 cm)(6 cm) = 42 cm^2

The area of the trapezium is 42 cm^2.

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4 years ago
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nevsk [136]

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3 years ago
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8 0
3 years ago
Y = 2x^2 + 3<br> im looking for how to find the axis of symmetry
andre [41]

The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0

<h3>How to determine the axis of symmetry?</h3>

The equation is given as:

y = 2x^2 + 3

Differentiate the above equation with respect to x

y' = 4x + 0

This gives

y' = 4x

Set the equation to 0

4x = 0

Divide both sides by 4

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Hence, the axis of symmetry is x = 0

Read more about axis of symmetry at:

brainly.com/question/1349456

4 0
2 years ago
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