Question

What is the equation of a line that goes through the point (0, -5) and has a slope of -3?

Answer 1

Answer:

y = -3x - 5

Step-by-step explanation:

The equation of a line is given as either:

$y = mx + b$  where m is the slope, and b is the y-intercept.

or

$y-y_{1} = m(x-x_{1} )$  where given that you have a point (x, y), y₁ is the y-value of the point, m is the slope, and x₁ is the x-value of the point.

We can just plug in the point (0, -5) into the second equation and -3 for the slope.

However, (0, -5) tells us that this point must be a y-intercept, since the x-value of that point is 0. So, we can also just plug into the first equation -5 for the y-intercept and -3 for the slope.

So, we get:

y = -3x + (-5)

Which simplifies into:

y = -3x - 5

Answer 2

Answer:

i dont know

Step-by-step explanation: