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andrew-mc [135]
3 years ago
9

Twelve of the 30 students in the class are boys. what is the ratio of boys to girls in the class

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

3:5 girls to boys I think is the ratio

Flura [38]3 years ago
3 0

Answer:

Attached below

Step-by-step explanation:

Boys to girls

12 to 18 or 12:18

4 to 6 or 4:6

\frac{12}{18} = \frac{4}{6}

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Whats the answer of -5+-2p=-9
Nikolay [14]

Answer:

p = 2

Step-by-step explanation:

Step 1: Write equation

-5 + -2p = -9

Step 2: Solve for <em>p</em>

<u>Simplify:</u> -5 - 2p = -9

<u>Add 5 to both sides:</u> -2p = -4

<u>Divide both sides by -2:</u> p = 2

Step 3: Check

<em>Plug in p to verify it's a solution.</em>

-5 - 2(2) = -9

-5 - 4 = -9

-9 = -9

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3 years ago
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A given line has the equation 2x+12y=-1.
PolarNik [594]
<span>2x+12y=-1
</span>y = -1x/6 -1/12

Perpendicular lines<span> are </span>lines<span> that cross one another at a 90° angle. They have slopes that are opposite reciprocals of one another. Therefore, the slope of the perpendicular line in this problem is the opposite reciprocal of -1/6 which is 6. The equation would be 

</span><span>y=(6)x+9</span>
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The sum of number y and sixty-one
Igoryamba
The answer is y+61 or 61+y.

Hope it helps
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A trinidadian who is planning to visit Canada changed $3192 to canadian currency. How many $ did the triodion received
DanielleElmas [232]

Answer:

$3934

Step-by-step explanation:

We know that the currency of different countries are different.

So, one US dollar = 1.23 Canadian dollar

Given : $3192

A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.

He exchanged $3192.

Therefore,

1 US dollar = 1.23 Canadian dollar

The value of $ 3192 will be equal to = 1.23 x 3192

                                                            = $ 3933.96

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8 0
3 years ago
13....................
Mashcka [7]

13.

(a)

y=-5x^2+21x-3

for x = 2:

y=-5(2)^2+21(2)-3=-20+42-3=19

for x = 5

y=-5(5)^2+21(5)-3=-125+105-3=-23

(b)

The graph is:

(c)

Using the graph:

\begin{gathered} x=1.8,y=18.6 \\ x=0.548,y=7 \\ x=3.65,y=7 \end{gathered}\begin{gathered} x=1.8 \\ y=-5(1.8)^2+21(1.8)-3=-16.2+37.8-3=18.6 \end{gathered}\begin{gathered} y=7 \\ -5x^2+21x-3=7 \\ -5x^2+21x-10=0 \end{gathered}

Using the quadratic formula:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}

6 0
1 year ago
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